**EQUATIONS AND
OTHER INFORMATION FOR CHM152L FINAL EXAM**

__Experiment A:__

MM: NaOH=40.00 g/mol

Heat Capacity in kJ/^{o}C:
C_{p} = ((55.90 kJ/mol)n)/(change in T)

Heat of Reaction in kJ/mol = -C_{p}(change
in T)/n

Where n = moles and T equals temperature

__Experiment B:__

General Reaction: E + S = ES = E + P

where E is the enzyme (papain), S is substrate (BAPNA),

P is products (p-nitroaniline), and ES is the enzyme-substrate complex.

p-nitroaniline is yellow in solution so its concentration can be directly related to the absorbance at the wavelength for maximum absorbance.

T=I/I_{o} A=-log_{10}(T)

__Experiment C:__ Synthesis of the iron salt

Percent by Mass = (part/whole)*100%

%yield = (Actual Yield/Theoretical Yield)/100%

__Experiment D:__ MM: NaSCN = 81.07 g/mol

Fe^{3+} + SCN^{-} = FeSCN^{2+}

K_{C} = [FeSCN^{2+}]/([Fe^{3+}][SCN^{-}])

Wavelenght for Maximum absorbance
for FeSCN^{2+} is 447 nm

Beer's Law: A = €lC where A is absorbance, € is molar absorptivity, l is path length, and C is concentration

__Experiment E:__ AW:
Fe=55.847g/mol K=39.098g/mol

pH = pK_{a} + log([A^{-}]/[HA])

Equivalent formula weight of the weak acid:

= (grams of weak acid)/(moles NaOH to reach equivalence point)

Moles NaOH = (liters NaOH)(molarity NaOH)

H^{+} + OH^{-} = H_{2}O
Fe^{3+} + 3OH^{-} = Fe(OH)_{3}
(1 mol Fe^{3+} reacts with 3 mol of OH^{-})

__Experiment F:__ MM g/mol Na_{2}C_{2}O_{4}=134.0
C_{2}O_{4}^{2-}=88.00 KMnO_{4}=158.04

2MnO_{4}^{-}+5C_{2}O_{4}^{-2}+16H^{+}
= 2Mn^{+2}+10CO_{2}+8H_{2}O

Conversion factors (obtained from the balanced reaction)

2 mole MnO_{4}^{-} reacts
with 5 mole C_{2}O_{4}^{-2}

Percent by Mass Na_{2}C_{2}0_{4} =
(g Na_{2}C_{2}0_{4})/g Unknown) x 100%

Additional Information:

Atomic Masses (g/mol): Na=23.00 O=16.00 S=32.06
Mg=24.31 C=12.01 H=1.008 Ca=40.08

Equation for linear regression:
y=mx+b

Median-: Middle Value Mean: Average Value Range = High-Low

Error = Absolute Value of the
Experimental Value – True Value

Relative Percent Error = (Error/True Value)
x 100%

Relative Percent Range = (Range/Median Value) x 100%